Optimal. Leaf size=129 \[ -\frac{x^{5/2}}{4 \left (x^2+1\right )^2}-\frac{5 \sqrt{x}}{16 \left (x^2+1\right )}-\frac{5 \log \left (x-\sqrt{2} \sqrt{x}+1\right )}{64 \sqrt{2}}+\frac{5 \log \left (x+\sqrt{2} \sqrt{x}+1\right )}{64 \sqrt{2}}-\frac{5 \tan ^{-1}\left (1-\sqrt{2} \sqrt{x}\right )}{32 \sqrt{2}}+\frac{5 \tan ^{-1}\left (\sqrt{2} \sqrt{x}+1\right )}{32 \sqrt{2}} \]
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Rubi [A] time = 0.068182, antiderivative size = 129, normalized size of antiderivative = 1., number of steps used = 12, number of rules used = 8, integrand size = 13, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.615, Rules used = {288, 329, 211, 1165, 628, 1162, 617, 204} \[ -\frac{x^{5/2}}{4 \left (x^2+1\right )^2}-\frac{5 \sqrt{x}}{16 \left (x^2+1\right )}-\frac{5 \log \left (x-\sqrt{2} \sqrt{x}+1\right )}{64 \sqrt{2}}+\frac{5 \log \left (x+\sqrt{2} \sqrt{x}+1\right )}{64 \sqrt{2}}-\frac{5 \tan ^{-1}\left (1-\sqrt{2} \sqrt{x}\right )}{32 \sqrt{2}}+\frac{5 \tan ^{-1}\left (\sqrt{2} \sqrt{x}+1\right )}{32 \sqrt{2}} \]
Antiderivative was successfully verified.
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Rule 288
Rule 329
Rule 211
Rule 1165
Rule 628
Rule 1162
Rule 617
Rule 204
Rubi steps
\begin{align*} \int \frac{x^{7/2}}{\left (1+x^2\right )^3} \, dx &=-\frac{x^{5/2}}{4 \left (1+x^2\right )^2}+\frac{5}{8} \int \frac{x^{3/2}}{\left (1+x^2\right )^2} \, dx\\ &=-\frac{x^{5/2}}{4 \left (1+x^2\right )^2}-\frac{5 \sqrt{x}}{16 \left (1+x^2\right )}+\frac{5}{32} \int \frac{1}{\sqrt{x} \left (1+x^2\right )} \, dx\\ &=-\frac{x^{5/2}}{4 \left (1+x^2\right )^2}-\frac{5 \sqrt{x}}{16 \left (1+x^2\right )}+\frac{5}{16} \operatorname{Subst}\left (\int \frac{1}{1+x^4} \, dx,x,\sqrt{x}\right )\\ &=-\frac{x^{5/2}}{4 \left (1+x^2\right )^2}-\frac{5 \sqrt{x}}{16 \left (1+x^2\right )}+\frac{5}{32} \operatorname{Subst}\left (\int \frac{1-x^2}{1+x^4} \, dx,x,\sqrt{x}\right )+\frac{5}{32} \operatorname{Subst}\left (\int \frac{1+x^2}{1+x^4} \, dx,x,\sqrt{x}\right )\\ &=-\frac{x^{5/2}}{4 \left (1+x^2\right )^2}-\frac{5 \sqrt{x}}{16 \left (1+x^2\right )}+\frac{5}{64} \operatorname{Subst}\left (\int \frac{1}{1-\sqrt{2} x+x^2} \, dx,x,\sqrt{x}\right )+\frac{5}{64} \operatorname{Subst}\left (\int \frac{1}{1+\sqrt{2} x+x^2} \, dx,x,\sqrt{x}\right )-\frac{5 \operatorname{Subst}\left (\int \frac{\sqrt{2}+2 x}{-1-\sqrt{2} x-x^2} \, dx,x,\sqrt{x}\right )}{64 \sqrt{2}}-\frac{5 \operatorname{Subst}\left (\int \frac{\sqrt{2}-2 x}{-1+\sqrt{2} x-x^2} \, dx,x,\sqrt{x}\right )}{64 \sqrt{2}}\\ &=-\frac{x^{5/2}}{4 \left (1+x^2\right )^2}-\frac{5 \sqrt{x}}{16 \left (1+x^2\right )}-\frac{5 \log \left (1-\sqrt{2} \sqrt{x}+x\right )}{64 \sqrt{2}}+\frac{5 \log \left (1+\sqrt{2} \sqrt{x}+x\right )}{64 \sqrt{2}}+\frac{5 \operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1-\sqrt{2} \sqrt{x}\right )}{32 \sqrt{2}}-\frac{5 \operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1+\sqrt{2} \sqrt{x}\right )}{32 \sqrt{2}}\\ &=-\frac{x^{5/2}}{4 \left (1+x^2\right )^2}-\frac{5 \sqrt{x}}{16 \left (1+x^2\right )}-\frac{5 \tan ^{-1}\left (1-\sqrt{2} \sqrt{x}\right )}{32 \sqrt{2}}+\frac{5 \tan ^{-1}\left (1+\sqrt{2} \sqrt{x}\right )}{32 \sqrt{2}}-\frac{5 \log \left (1-\sqrt{2} \sqrt{x}+x\right )}{64 \sqrt{2}}+\frac{5 \log \left (1+\sqrt{2} \sqrt{x}+x\right )}{64 \sqrt{2}}\\ \end{align*}
Mathematica [A] time = 0.0444045, size = 135, normalized size = 1.05 \[ \frac{1}{384} \left (-\frac{256 x^{5/2}}{\left (x^2+1\right )^2}+\frac{40 \sqrt{x}}{x^2+1}-\frac{160 \sqrt{x}}{\left (x^2+1\right )^2}-15 \sqrt{2} \log \left (x-\sqrt{2} \sqrt{x}+1\right )+15 \sqrt{2} \log \left (x+\sqrt{2} \sqrt{x}+1\right )-30 \sqrt{2} \tan ^{-1}\left (1-\sqrt{2} \sqrt{x}\right )+30 \sqrt{2} \tan ^{-1}\left (\sqrt{2} \sqrt{x}+1\right )\right ) \]
Antiderivative was successfully verified.
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Maple [A] time = 0.009, size = 82, normalized size = 0.6 \begin{align*} 2\,{\frac{1}{ \left ({x}^{2}+1 \right ) ^{2}} \left ( -{\frac{9\,{x}^{5/2}}{32}}-{\frac{5\,\sqrt{x}}{32}} \right ) }+{\frac{5\,\sqrt{2}}{64}\arctan \left ( 1+\sqrt{2}\sqrt{x} \right ) }+{\frac{5\,\sqrt{2}}{64}\arctan \left ( -1+\sqrt{2}\sqrt{x} \right ) }+{\frac{5\,\sqrt{2}}{128}\ln \left ({ \left ( 1+x+\sqrt{2}\sqrt{x} \right ) \left ( 1+x-\sqrt{2}\sqrt{x} \right ) ^{-1}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 2.9388, size = 134, normalized size = 1.04 \begin{align*} \frac{5}{64} \, \sqrt{2} \arctan \left (\frac{1}{2} \, \sqrt{2}{\left (\sqrt{2} + 2 \, \sqrt{x}\right )}\right ) + \frac{5}{64} \, \sqrt{2} \arctan \left (-\frac{1}{2} \, \sqrt{2}{\left (\sqrt{2} - 2 \, \sqrt{x}\right )}\right ) + \frac{5}{128} \, \sqrt{2} \log \left (\sqrt{2} \sqrt{x} + x + 1\right ) - \frac{5}{128} \, \sqrt{2} \log \left (-\sqrt{2} \sqrt{x} + x + 1\right ) - \frac{9 \, x^{\frac{5}{2}} + 5 \, \sqrt{x}}{16 \,{\left (x^{4} + 2 \, x^{2} + 1\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.37088, size = 518, normalized size = 4.02 \begin{align*} -\frac{20 \, \sqrt{2}{\left (x^{4} + 2 \, x^{2} + 1\right )} \arctan \left (\sqrt{2} \sqrt{\sqrt{2} \sqrt{x} + x + 1} - \sqrt{2} \sqrt{x} - 1\right ) + 20 \, \sqrt{2}{\left (x^{4} + 2 \, x^{2} + 1\right )} \arctan \left (\frac{1}{2} \, \sqrt{2} \sqrt{-4 \, \sqrt{2} \sqrt{x} + 4 \, x + 4} - \sqrt{2} \sqrt{x} + 1\right ) - 5 \, \sqrt{2}{\left (x^{4} + 2 \, x^{2} + 1\right )} \log \left (4 \, \sqrt{2} \sqrt{x} + 4 \, x + 4\right ) + 5 \, \sqrt{2}{\left (x^{4} + 2 \, x^{2} + 1\right )} \log \left (-4 \, \sqrt{2} \sqrt{x} + 4 \, x + 4\right ) + 8 \,{\left (9 \, x^{2} + 5\right )} \sqrt{x}}{128 \,{\left (x^{4} + 2 \, x^{2} + 1\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [B] time = 44.6923, size = 481, normalized size = 3.73 \begin{align*} - \frac{72 x^{\frac{5}{2}}}{128 x^{4} + 256 x^{2} + 128} - \frac{40 \sqrt{x}}{128 x^{4} + 256 x^{2} + 128} - \frac{5 \sqrt{2} x^{4} \log{\left (- 4 \sqrt{2} \sqrt{x} + 4 x + 4 \right )}}{128 x^{4} + 256 x^{2} + 128} + \frac{5 \sqrt{2} x^{4} \log{\left (4 \sqrt{2} \sqrt{x} + 4 x + 4 \right )}}{128 x^{4} + 256 x^{2} + 128} + \frac{10 \sqrt{2} x^{4} \operatorname{atan}{\left (\sqrt{2} \sqrt{x} - 1 \right )}}{128 x^{4} + 256 x^{2} + 128} + \frac{10 \sqrt{2} x^{4} \operatorname{atan}{\left (\sqrt{2} \sqrt{x} + 1 \right )}}{128 x^{4} + 256 x^{2} + 128} - \frac{10 \sqrt{2} x^{2} \log{\left (- 4 \sqrt{2} \sqrt{x} + 4 x + 4 \right )}}{128 x^{4} + 256 x^{2} + 128} + \frac{10 \sqrt{2} x^{2} \log{\left (4 \sqrt{2} \sqrt{x} + 4 x + 4 \right )}}{128 x^{4} + 256 x^{2} + 128} + \frac{20 \sqrt{2} x^{2} \operatorname{atan}{\left (\sqrt{2} \sqrt{x} - 1 \right )}}{128 x^{4} + 256 x^{2} + 128} + \frac{20 \sqrt{2} x^{2} \operatorname{atan}{\left (\sqrt{2} \sqrt{x} + 1 \right )}}{128 x^{4} + 256 x^{2} + 128} - \frac{5 \sqrt{2} \log{\left (- 4 \sqrt{2} \sqrt{x} + 4 x + 4 \right )}}{128 x^{4} + 256 x^{2} + 128} + \frac{5 \sqrt{2} \log{\left (4 \sqrt{2} \sqrt{x} + 4 x + 4 \right )}}{128 x^{4} + 256 x^{2} + 128} + \frac{10 \sqrt{2} \operatorname{atan}{\left (\sqrt{2} \sqrt{x} - 1 \right )}}{128 x^{4} + 256 x^{2} + 128} + \frac{10 \sqrt{2} \operatorname{atan}{\left (\sqrt{2} \sqrt{x} + 1 \right )}}{128 x^{4} + 256 x^{2} + 128} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 2.0662, size = 127, normalized size = 0.98 \begin{align*} \frac{5}{64} \, \sqrt{2} \arctan \left (\frac{1}{2} \, \sqrt{2}{\left (\sqrt{2} + 2 \, \sqrt{x}\right )}\right ) + \frac{5}{64} \, \sqrt{2} \arctan \left (-\frac{1}{2} \, \sqrt{2}{\left (\sqrt{2} - 2 \, \sqrt{x}\right )}\right ) + \frac{5}{128} \, \sqrt{2} \log \left (\sqrt{2} \sqrt{x} + x + 1\right ) - \frac{5}{128} \, \sqrt{2} \log \left (-\sqrt{2} \sqrt{x} + x + 1\right ) - \frac{9 \, x^{\frac{5}{2}} + 5 \, \sqrt{x}}{16 \,{\left (x^{2} + 1\right )}^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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